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Made in ch
Regular Dakkanaut




Zürich

The codex says that 1 in 3 models may take a fusion blaster. Until now I just assumed that it meant in order to have 2 fusion blasters you have to have 6 models, however now I'm not so sure. Could one have 2 fusion blasters with only 4 models in the unit ?

-"Subtle is subjective, of course; in a finesseless game like 40K, anything that isn't a brick to the head is downright sneaky..." ->lord_sutekh 
   
Made in us
Master of the Hunt





Angmar

That's usually how people read that in my experience. 1 for 3, 2 for 4+.

"It is by caffeine alone I set my mind in motion.
It is by the seed of Arabica that thoughts acquire speed, the teeth acquire stains, the stains become a warning.
It is by caffeine alone I set my mind in motion."
 
   
Made in us
Longtime Dakkanaut





Silverdale, WA

I've had the exact opposite experience. Everyone around here (myself included) has always read that as a 1/3 ratio of fusion blasters to burst cannons. Even reading it now I can't see it the other way. Of course, flavious or someone else who has a better grasp on the english language than me can probably reveal how this is just another one in a long line of poorly phrased rules passages.

 
   
Made in jp
[MOD]
Anti-piracy Officer






Somewhere in south-central England.

I read it the other way -- convert 1 out of 3 figures from burst to fusion means you need a unit of 6 to have 2 fusion.

I'm writing a load of fiction. My latest story starts here... This is the index of all the stories...

We're not very big on official rules. Rules lead to people looking for loopholes. What's here is about it. 
   
Made in ee
Regular Dakkanaut




Zürich

Anyone else ?

-"Subtle is subjective, of course; in a finesseless game like 40K, anything that isn't a brick to the head is downright sneaky..." ->lord_sutekh 
   
Made in gb
Sagitarius with a Big F'in Gun






I read it:

One in every complete set of three may have a fusion blaster, so you would need two complete sets of three to have two fusion blasters.

Four or five Stealthsuits only form one complete set of three (and one incomplete set), so could only have one fusion blaster.

   
Made in us
Plastictrees



Amongst the Stars, In the Night

I see it as a mathematical ratio in written form which requires a minimum (rather than a maximum) of three stealth suits to get one armed with a fusion blaster. Ergo, you can't get a second one until there are six stealth suits in the squad.

OT Zone: A More Wretched Hive of Scum and Villany
The Loyal Slave learns to Love the Lash! 
   
Made in us
[DCM]
Sentient OverBear






Clearwater, FL

I agree with Cpl Saint and Nyarly.  A little clarification of my viewpoint would be to break up the squad into groups of three.  If you have four total models in the squad, the first group would have three models, so it could have a fusion blaster.  The second group would have one model, so it couldn't get the fusion blaster (it's a one in one, not a one in three).

For the mathematically inclined, think modulo.

DQ:70S++G+++M+B++I+Pw40k94+ID+++A++/sWD178R+++T(I)DM+++

Trust me, no matter what damage they have the potential to do, single-shot weapons always flatter to deceive in 40k.                                                                                                       Rule #1
- BBAP

 
   
Made in jp
[MOD]
Anti-piracy Officer






Somewhere in south-central England.

I suppose this is the logic for another point of view.

Buy a squad of 6 stealth.
Convert a burst cannon to fusion.
You still have more than three burst cannons so do it again.
And again.
And again.
Now you only have two burst cannons left so you can't convert any more.

It might be an interesting unit to play with but I think there would be a lot of arguing with your opponent.

I'm writing a load of fiction. My latest story starts here... This is the index of all the stories...

We're not very big on official rules. Rules lead to people looking for loopholes. What's here is about it. 
   
Made in us
Foul Dwimmerlaik






Minneapolis, MN

1. Burst cannon
2. Burst cannon
3. Fusion blaster
4. Burst cannon
5. Burst cannon
6. Fusion blaster


Though I do understand how people see it that you can take two for 4+, but my interpretation is that it infers a multiple of three.

Since we are dealing with a multiple of three, and 4 isnt a multiple of three, you must have six figs to use two fusion blasters.

Same thing with eldar jetbikes upgrading shuricannons, space wolf termie heavy weapons, etc.

Instead of 1-3 gets one fusion, 4-6 gets two fusion, I see it as 3-5 gets one fusion, 6-8 gets two fusion.

   
Made in us
Longtime Dakkanaut





Silverdale, WA

Posted By Iorek on 01/31/2007 7:57 AM
I agree with Cpl Saint and Nyarly.

 

Psssh!  Those guys are way off!  I think glaive and killkrazy are on the right track though.


 
   
Made in us
Foul Dwimmerlaik






Minneapolis, MN

Posted By Glaive Company CO on 01/31/2007 10:17 AM
Posted By Iorek on 01/31/2007 7:57 AM
I agree with Cpl Saint and Nyarly.

 

Psssh!  Those guys are way off!  I think glaive and killkrazy are on the right track though.


Nah those guys are n0obz. Hellfury is waaaay more right than those freaks. He is cooler as well.

"There was this one time, at band camp, where Salma Hayek asked me to pee in her butt....."

   
 
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