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		<title><![CDATA[Latest posts for the thread "Dice to hit question"]]></title>
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				<title>Dice to hit question</title>
				<description><![CDATA[ I am horrible at math, lets say on a <span class="glossaryitem" onmouseover='gp(341);'>d20</span> a four or less is a miss, how accurately could this be translated to represent this roll on a <span class="glossaryitem" onmouseover='gp(24);'>d6</span>  on a  <span class="glossaryitem" onmouseover='gp(342);'>d10</span> and a <span class="glossaryitem" onmouseover='gp(343);'>d12</span>?]]></description>
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				<pubDate><![CDATA[Fri, 28 Jun 2013 07:05:25]]> GMT</pubDate>
				<author><![CDATA[ commissar80]]></author>
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				<title>Dice to hit question</title>
				<description><![CDATA[ So that's 4 in 20 or 1/5<br /> <br /> Closest on a <span class="glossaryitem" onmouseover='gp(24);'>d6</span> is 1/6 (so any single number)<br /> <br /> Closest on a <span class="glossaryitem" onmouseover='gp(342);'>d10</span> would be 2 /10 (so any two numbers, and exactly the same)<br /> <br /> Closest on a <span class="glossaryitem" onmouseover='gp(343);'>D12</span> is either 2 or 3 numbers (giving 1/6 or 1/4)]]></description>
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				<pubDate><![CDATA[Fri, 28 Jun 2013 08:09:34]]> GMT</pubDate>
				<author><![CDATA[ Koppo]]></author>
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				<title>Re:Dice to hit question</title>
				<description><![CDATA[ ok cool now what about a 15 or better on a <span class="glossaryitem" onmouseover='gp(341);'>d20</span>, I think it would be the same as stated previously, correct, <blockquote class="uncited"><div>So that's 4 in 20 or 1/5<br /> <br /> Closest on a <span class="glossaryitem" onmouseover='gp(24);'>d6</span> is 1/6 (so any single number)<br /> <br /> Closest on a <span class="glossaryitem" onmouseover='gp(342);'>d10</span> would be 2 /10 (so any two numbers, and exactly the same)<br /> <br /> Closest on a <span class="glossaryitem" onmouseover='gp(343);'>D12</span> is either 2 or 3 numbers (giving 1/6 or 1/4)]]></description>
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				<pubDate><![CDATA[Fri, 28 Jun 2013 18:48:53]]> GMT</pubDate>
				<author><![CDATA[ commissar80]]></author>
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				<title>Dice to hit question</title>
				<description><![CDATA[ Just work out the percentages for success.<br /> It's not hard.<br /> Divide 100 by the number of faces.<br /> To get the chance of success multiply that number by the number of faces that would succeed.<br /> So 15 or better on a <span class="glossaryitem" onmouseover='gp(341);'>d20</span>.<br /> 6 chances to succeed on one dice 15,16,17,18,19, 20.<br /> 100/20=5<br /> 5*6=30<br /> you therefore have a 30% chance to succeed<br /> ]]></description>
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				<pubDate><![CDATA[Fri, 28 Jun 2013 19:13:08]]> GMT</pubDate>
				<author><![CDATA[ marv335]]></author>
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				<title>Dice to hit question</title>
				<description><![CDATA[ Every tick on a die is worth 1 divided by the number of faces percent.<br /> <br /> So on a <span class="glossaryitem" onmouseover='gp(341);'>d20</span>, 1/20 = 5%.<br /> <span class="glossaryitem" onmouseover='gp(24);'>d6</span>, 1/6 = ~17%<br /> <br /> So to equal the 'probabilty' of 1 result on a <span class="glossaryitem" onmouseover='gp(24);'>d6</span>, you would capture between 4 and 5 results on a <span class="glossaryitem" onmouseover='gp(341);'>d20</span>.]]></description>
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				<pubDate><![CDATA[Fri, 28 Jun 2013 20:30:01]]> GMT</pubDate>
				<author><![CDATA[ sourclams]]></author>
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