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		<title><![CDATA[Latest posts for the thread "Binomial Distributions"]]></title>
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				<title>Binomial Distributions</title>
				<description><![CDATA[ Having trouble with binomial distributions can't figure out part "a".<br /> <br /> 28.	Frogs.  A wildlife biologist examines frogs for a genetic trait he suspects may be linked to sensitivity to industrial toxins in the environment.  Previous research had established that this trait is usually found in 1 of every 8 frogs.   He collects and examines a dozen frogs.  If the frequency of the trait has not changed, what’s the probability he finds the trait in<br /> a)	none of the 12 frogs?<br /> b)	at least 2 frogs?<br /> c)	3 or 4 frogs?<br /> d)	no more than 4 frogs?<br /> <br /> Is this correct so far for part "a"?<br /> p=0<br /> x=0<br /> n=8<br /> q=1<br /> n-x=8]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 06:10:04]]> GMT</pubDate>
				<author><![CDATA[ Cheesecat]]></author>
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				<title>Binomial Distributions</title>
				<description><![CDATA[ p = 1/8<br /> q = 7/8<br /> n = 12<br /> x = 0<br /> n-x = 12]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 06:38:09]]> GMT</pubDate>
				<author><![CDATA[ Dheneb]]></author>
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				<title>Re:Binomial Distributions</title>
				<description><![CDATA[ Thanks for part "b" am I calculating just p(2) or 1-p(2)?]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 07:04:29]]> GMT</pubDate>
				<author><![CDATA[ Cheesecat]]></author>
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				<title>Binomial Distributions</title>
				<description><![CDATA[ 1 - ( P(0) + P(1) ) actually.]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 07:15:53]]> GMT</pubDate>
				<author><![CDATA[ Dheneb]]></author>
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				<title>Re:Binomial Distributions</title>
				<description><![CDATA[ for part "c" I added p(1) + p(2) + p(3) + p(4) = 0.393 + 0.311 + 0.282 + 0273 = 1.259 I think something went wrong as it shouldn't be higher than 1.]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 08:10:28]]> GMT</pubDate>
				<author><![CDATA[ Cheesecat]]></author>
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				<title>Binomial Distributions</title>
				<description><![CDATA[ For c it's just P(3) + P(4). Are you sure you're putting the numbers in right? I got 0.345 + 0.271 + 0.129 + 0.042 = 0.787]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 08:33:44]]> GMT</pubDate>
				<author><![CDATA[ Dheneb]]></author>
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				<title>Re:Binomial Distributions</title>
				<description><![CDATA[ Well for p(1) I pressed [8] + [nCr] + [1] + [X] + [0.125] + [yx] + [1] + [X] + [0.875] + [yx] + [7] = [0.393] on my TI-30XA.]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 08:48:28]]> GMT</pubDate>
				<author><![CDATA[ Cheesecat]]></author>
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				<title>Binomial Distributions</title>
				<description><![CDATA[ n is the number of trials, in this case the number of frogs caught.]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 09:01:06]]> GMT</pubDate>
				<author><![CDATA[ Dheneb]]></author>
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				<title>Binomial Distributions</title>
				<description><![CDATA[ <blockquote><div><img src="https://www.dakkadakka.com/s/i/a/fbebc4714cc96832328fcc2e69862070.jpg" height="20" border="0">&nbsp;<a href="/dakkaforum/posts/preList/579656/6536909.page"><b>Dheneb wrote:</b></a><br/>n is the number of trials, in this case the number of frogs caught.</div></blockquote><br /> <br /> OK, but am I putting in the right buttons?]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 09:03:00]]> GMT</pubDate>
				<author><![CDATA[ Cheesecat]]></author>
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				<title>Binomial Distributions</title>
				<description><![CDATA[ Yeah. Right buttons but wrong numbers.]]></description>
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				<pubDate><![CDATA[Thu, 13 Feb 2014 09:56:49]]> GMT</pubDate>
				<author><![CDATA[ Dheneb]]></author>
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