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There are 36 unique possible combination, and 6 of them are doubles, so that's 6/36 chances (and since 6 goes into 36, 6 times, this reduces to 1/6) or about 17%.

Tervigon says on a roll of any double (w/ 3 dice) it will exhaust his ability to produce termagaunts. Im really tired and I dont want to figure out the math. Curious if anyone already knows it and could answer my question, Its almost 9 am.. and i need to go to bed .

Thx.

44.4444...% chance or to roll doubles on 3 dice or 4/9 chance per roll.

Numbers of particular concern;
18 and 3 obviously have a 100% chance of rolling doubles. (I sincerely hope that no one in the gaming comunity attempts to argue that rolling tripps is not rolling doubles)
17 and 4 also have a 100% chance of rolling doubles.
15 and 6 have a 60% chance of rolling doubles

Your "safest" numbers are 12 and 9 at 28% chance to yield doubles.

I think it's wise to make sure your beast is in position before he starts giving birth because there's a good chance he won't have another opportunity.

I figured it was close to 50% but wasnt sure. Guess I wont be using him. Taking up an HQ slot and with that high problability makes it not worth it. Also, I dont want to buy or paint termaguants... I rather get gargs.

Thx man!

You can make the tervigon a troop choice by taking termagaunts. However, I will not be using it either.

Its a scoring MC, with regeneration and casts catalyst on whatever you need it. Onslaught if you are using hive guard.

The Tervigon is a force multiplier. Its not a bug-farm.

Crapping out a free scoring unit or two is cute, but is not it's primary purpose.

incarna wrote:44.4444...% chance or to roll doubles on 3 dice or 4/9 chance per roll.

Numbers of particular concern;
18 and 3 obviously have a 100% chance of rolling doubles. (I sincerely hope that no one in the gaming comunity attempts to argue that rolling tripps is not rolling doubles)
17 and 4 also have a 100% chance of rolling doubles.
15 and 6 have a 60% chance of rolling doubles

Your "safest" numbers are 12 and 9 at 28% chance to yield doubles.

I think it's wise to make sure your beast is in position before he starts giving birth because there's a good chance he won't have another opportunity.

There are 216 outcomes on 3 dice.

36 on two dice. There are 6 possible combinations of doubles on two dice. That would be a 17% chance that doubles are rolled. On three dice, there's 18 ways to roll doubles. That would make doubles come up at around 8% (lowered because of the increased number of outcomes). Add triples in and there are only 24 possible combinations of doubles and triples. 24 out of 216 possible combinations. That's 11% chance to roll doubles or triples. Or, if you want to break it down further, 8% to roll doubles and 3% to roll triples.

I don't care what the % are. I played vs 1 of those bastards this week and he got out 22 gaunts before rolling the "dreaded" doubles. I can only imagine what the armies that are taking 3 or 4 of them can manage to put out.

All scoring. All the time. Crazy.

And for those thinking "but their KP" - go away because tabling your opponent is a win every time.

incarna wrote:

Your "safest" numbers are 12 and 9 at 28% chance to yield doubles.

Please explain this to me. Across 3 dice, there are 3 ways to roll double sixes. That's 3/216. That's a little over 1%. In fact, -any- combination of 3 numbers (for doubles) is going to be 3/216. Triples is 6/216, across all dice. Triples is also 3/216 of any particular number.

puma713 wrote:

incarna wrote:

Your "safest" numbers are 12 and 9 at 28% chance to yield doubles.

Please explain this to me. Across 3 dice, there are 3 ways to roll double sixes. That's 3/216. That's a little over 1%. In fact, -any- combination of 3 numbers (for doubles) is going to be 3/216. Triples is 6/216, across all dice. Triples is also 3/216 of any particular number.

Your math is wrong because it's not taking into account that for each roll of doubles, there is a third die. For example, these are all separate rolls:

661
662
663
664
665
616
626
636
646
656
166
266
366
466
566
666


So there is actually 16 different combinations for each double (5 x 3 different positions + 1 for triples).

16 x 6 = 96.

96/216 = 0.44

44%. He was right.

Your math doesnt even make sense logically. There was a 16% chance to roll doubles before on 2 dice, and now all youve done is add the third die, which would only increase the odds.

Night Lords wrote:

puma713 wrote:

incarna wrote:

Your "safest" numbers are 12 and 9 at 28% chance to yield doubles.

Please explain this to me. Across 3 dice, there are 3 ways to roll double sixes. That's 3/216. That's a little over 1%. In fact, -any- combination of 3 numbers (for doubles) is going to be 3/216. Triples is 6/216, across all dice. Triples is also 3/216 of any particular number.

Your math is wrong because it's not taking into account that for each roll of doubles, there is a third die. For example, these are all separate rolls:

661
662
663
664
665
616
626
636
646
656
166
266
366
466
566
666


So there is actually 16 different combinations for each double (5 x 3 different positions + 1 for triples).

16 x 6 = 96.

96/216 = 0.44

44%. He was right.

Your math doesnt even make sense logically. There was a 16% chance to roll doubles before on 2 dice, and now all youve done is add the third die, which would only increase the odds.

You're right. My math is wrong. 96/216 outcomes include doubles. Apologies, incarna.