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So I recently bought the WOTR rulebook, and this is one of the rules I don't get. If you have 8 hits for example and the foe has 2 resilience, do you roll on the Hard to Kill chart 4 times? Wouldn't that effectly mean the defence stat is pointless then?

You are correct, if you have eight hits on a model with two resilience then you roll on the hard to kill chart four times. (Remember the hard to kill chart only applies to certain models. Other models will be killed outright.) However, the defence stat is not useless. It is used in calculating hits. See the to hit chart on page 322.

Some monsters are relatively easy to kill like cave trolls, while others are very difficult like Mumaks. In general, models with the hard to kill ability are better when they are fielded in large numbers.

Sorry I'm still confused. So where does the defense stat come into play then if you're against a Hard to Kill model? Say if a formation with 8 charges a Mordor troll for example, then that'll make 4 hits on the Hard to Kill chart. The first hit scores a 6, wouldn't that mean the troll is dead without any use for the defense stat?

I think you are confusing attacks with hits.

Your formation of infantry charges a troll.
The troll swings first. He has 4 attacks, and a fight of 7 to your fight of 3, so he gets three more dice for battle skill, for a total of 7 dice.*
Compare the troll's strength of 7 to your defense of 3 on the chart. If I recall correctly, he hits you on a 3+. So the troll rolls 7 dice, and scores 6, 5, 4, 4, 3, 3, 1, for a total of 6 hits. You lose 6 warriors from the back of your formation- somewhere not in combat.

Now your infantry can attack. Only one stand can be in contact with the troll, due to his round base, so you get 8 base attacks +1 for charging for a total of 9 dice (nothing for battle skill as your fight is not higher than the troll's). Go to the chart and compare your strength of 3 to the troll's defense of 7. I think you need 6's. So you roll and get 6, 6, 6, 6, 6, 3, 2, 2, 1, for a total of 5 hits.
The troll is resilience 2, so four of your hits count (as two), and the third is ignored, lost, soaked up.
So now you get two rolls on the Hard to Kill table. You take you single die and roll. If you roll a one, nothing happens. If you roll a six, the troll dies. Any other roll results in at least one wound counter being placed on the troll. For your first roll, you get a 5- two wound counters to the troll. Your next roll is a 4, plus two from the wound counters makes six, and the troll dies. Wound counters are persistent, cumulative plusses to rolls on the Hard-to-Kill table.

Check out this thread for answers to more questions.


*7-3 = 4. Four more hits, eight dice. Math, feh! Treat all numbers and stats in this post as notional, I don't have the book with me.

You do not understand how hitting works in the game. All units in the game, except characters, have an A (attack) stat. This is not the number of hits, rather, it is the base number of dice that you roll to hit. (This number of dice is modified by various factors such as fight, being flanked, etc.) Roll the modified number of dice and consult the to hit chart on page 322. Find the row that corresponds to the strength of the unit that is attacking, and go across until you reach the column that corresponds to the defense of the unit being attacked. Every dice that equals or exceeds the number in that box is a hit.

Normally for every hit a model is removed. Models with resilience two require two hits to remove a model. Hard to kill models are not removed when they have taken a number of hits equal to their resilience. Instead you roll on the hard to kill chart. If a hard to kill model gets a wound counter, that counter is added to future dice rolls on the hard to kill chart.

Ah okay, I get it now. Thanks .