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So I am new to this and have DA codex. I am not sure how to use Ezekiel's mind worm any takers.

assault D3 means you roll everytime you "shoot" it to see how many shots you get

It means that they can shoot a random number of shots. The d3 refers to a 3 sided dice, and you'll commonly see a d6, which means roll a dice.

Since there is no such thing as a d3, simply roll a 6 sided dice and a 1-2 is a 1, a 3-4 is a 2, and a 5-6 is a 3.

So if I roll a 3 I get to use his power potential twice if the first one fails?

No you use it once but it fires 3 shots

No - but if the power succeeds you can roll to hit 3 times.

Ok I get it now I think, as it is D3 and I roll a 3 I get to hit twice?

Twice? From three? Why twice?
You roll 3 you get to shoot 3 times.

I thought as it was D3 you get 1-2 as 1 3-4 as 2 ect

1-2 = 1
3-4 = 2
5-6 = 3

It's a D3 so the range is 1 to 3.

Did you mean roll a 3 on a D6? Not a D3?
If so yes, a 3 would equal 2 sorry.

Yes that's right so you get to hit any where between 1 & 3 times.

Usually players roll a D6 and count 1,2 =1, 3,4=2 and 5,6=3.

I'll be a bit obvious, maybe redundant, bear with me..

Now, let's assume you want to use this power (I don't have the codex with me, I'll approximate):
First, you declare the power and make a psychic test
If you succeed, D3... The D6 shows a 3, so it means two attacks
Now you roll two (the d3 result) To Hit rolls, and eventually To Wound, then allocate... the rest is pretty normal

I tend towards using (1,4)=1, (2,5)=2, and (3,6)=3. That way the face of the die is easier to read since the 1,2,3 parts match up, no interpretation necessary.

That said whatever system you use is fine just so long as you and your opponents know what you are rolling for.

the d3 in this case means the weapon fires a random number of shots from 1-3 each time you use it, so roll to determine the amount of shots fired by the gun whenever you do so.

If you want to be a stickler for the rules. Take the d6 result and divide by 2 rounding up to get the result of a d3. Basically what Ouze posted above. Page 5 of the BRB.