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![[Post New]](/s/i/i.gif) 2016/06/03 20:22:41
Subject: Need Help with Mathhammer!
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Regular Dakkanaut
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Hello! I have been having difficulty mathhammering recently, especially in the psychic phase.
My scenario is casting a WC3 spell with 7dice.
I have found the charts that tell me what the percentages are, and I can find out what the percent chance of succeeding would be if I drew a tree diagram, but I was wondering is there an easier way to express this mathematically?
Finding a success of a WC3 spell with 3 dice is simple but I lose track when it gets to rolling three 4+'s on four dice. I can count the outcomes from four dice and give a fraction (5/16) but that becomes quite cumbersome at seven dice. Could someone with a better understanding of probability help me out? Thanks!
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![[Post New]](/s/i/i.gif) 2016/06/03 21:04:27
Subject: Need Help with Mathhammer!
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Longtime Dakkanaut
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You don't have to be happy when you lose, just don't make winning the condition of your happiness. |
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![[Post New]](/s/i/i.gif) 2016/06/03 22:25:30
Subject: Need Help with Mathhammer!
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Potent Possessed Daemonvessel
Why Aye Ya Canny Dakkanaughts!
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Pascals triangle seems to work well for me.
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Ghorros wrote:The moral of the story: Don't park your Imperial Knight in a field of Gretchin carrying power tools.
Marmatag wrote:All the while, my opponent is furious, throwing his codex on the floor, trying to slash his wrists with safety scissors. |
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![[Post New]](/s/i/i.gif) 2016/06/04 00:58:29
Subject: Re:Need Help with Mathhammer!
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Douglas Bader
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What you're looking for is binomial probability: the chance of getting X or more successes out of Y attempts at Z% odds. Here is a calculator: http://stattrek.com/online-calculator/binomial.aspx
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There is no such thing as a hobby without politics. "Leave politics at the door" is itself a political statement, an endorsement of the status quo and an attempt to silence dissenting voices. |
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![[Post New]](/s/i/i.gif) 2016/06/04 03:46:57
Subject: Need Help with Mathhammer!
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Longtime Dakkanaut
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Here's some easy ones that are pretty good, without having to break out the calculator!
WC1 power succeeds 50% of the time with 1 die.
WC2 power succeeds 50% of the time with 3 dice
WC3 power succeeds 50% of the time with 5 dice.
After that, each additional dice gets you 1/(WC+1)% of the way towards 100%. It's not perfectly accurate (actually, it is with WC1 powers), but it's close enough for mental stuff. So, without checking, if 5 dice on WC3 nets a 50% return, 6 dice gives you just about a 65% chance, and 7 dice would be about 75%. Checking the calculator, I see that I'm only off by about 2%.
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Galef wrote:If you refuse to use rock, you will never beat scissors. |
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![[Post New]](/s/i/i.gif) 2016/06/11 17:50:32
Subject: Need Help with Mathhammer!
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Regular Dakkanaut
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Thanks, these are all a great help!
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