Talamare wrote:Chance of double 1s is 1 in 36
1/36 = 0.0277
2.7% chance
It happening 4x is
(1/36)^4 = 0.000000595
or 0.0000595%
Happening 4 time out of 7 is not the same as happening 4 times out of 4 (which is what you calculated).
You have to work out the combinations (nCr).
No. of double 1s - combinations:
0 - 1
1 - 7
2 - 21
3 - 35
4 - 35
5 - 21
6 - 7
7 - 1
So, 4 double 1s out of 7 attempts happens 35 times out of 128 possibles.
Then you work out the odds of that specific result
1/35 x 1/35 x 1/35 x 1/35 x 35/36 x 35/36 x 35/36
and multiply it by the number of combinations (35) for a result of 0.0000191
If we work that out for all of the different results the distribution looks like this.
No. of double 1s - probability:
0 - 0.821
1 - 0.164
2 - 0.0141
3 - 0.000669
4 - 0.0000191
5 - 0.000000328
6 - 0.00000000132
7 - 0 (not really zero but so close, who cares? 1/(2.8x10^12) for those that do.)
(NB When you're making a probability distribution you check your work by adding up all of the results. They should add up to 1 (usually a fraction under due to the decimal places you couldn't be bothered putting in). If they don't then you've screwed up)
TL;DR
So that's a 1 in 50,000 chance of rolling 4x double 1s out of 7 attempts. (The odds of 4 or more are only slightly more likely)
Also, 82% of the time you'll make 7 tests without rolling any double 1s. Only 2% of the time will you roll double 1s more than once.